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S  0, ``  X*  0 `   Z*  0 `   Z*z  bA޽h @ ?Parchment ̙33 Default Design 0 zr@ ( )   0̩ P    P*    0ԭ     R*  d  c $ ?    0p  @  RClick to edit Master text styles Second level Third level Fourth level Fifth level!     S  6 `P   P*    6 `   R*  H  0޽h ? ̙3380___PPT10.YzqR 0X(   $+ X X 0 P    X*  X 0     Z*  X 6  `P   X*  X 6 `   Z* H X 0޽h ? ̙3380___PPT10.YR 0L0  P+(     0ǝ~ /IONISATION ENERGY A guide for A level students b/(28(26f<fff  0ϝ(H OKNOCKHARDY PUBLISHING(2 fJ  C "A KTRE  " <̙? x @ 0 0 ( <̙? x @L 0 0 + 0pӝ"`>B 2008 SPECIFICATIONS<G$G   B  s *޽h ? ̙33y___PPT10Y+D=' = @B +  0L0 ` (    0  _IONISATION ENERGY2(2(f<fdB  <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0I   0p$p INTRODUCTION This Powerpoint show is one of several produced to help students understand selected topics at AS and A2 level Chemistry. It is based on the requirements of the AQA and OCR specifications but is suitable for other examination boards. Individual students may use the material at home for revision purposes or it may be used for classroom teaching if an interactive white board is available. Accompanying notes on this, and the full range of AS and A2 topics, are available from the KNOCKHARDY SCIENCE WEBSITE at... www.knockhardy.org.uk/sci.htm Navigation is achieved by... either clicking on the grey arrows at the foot of each page or using the left and right arrow keys on the keyboard (2 2(2 2   75, dB   <D?     0,{0P( OKNOCKHARDY PUBLISHING(2 B  s *޽h ? ̙33y___PPT10Y+D=' = @B +  0L0   pj (    0@ _IONISATION ENERGY2(2(f<f+  0&8   CONTENTS What is Ionisation Energy? Definition of 1st Ionisation Energy What affects Ionisation Energy? General variation across periods Variation down groups Variation in the first twelve elements Successive Ionisation Energies Questions Check listL (202 2P   z #dB  <D)P0Q  0Pp@ 0 0dB  @ <D)PXP   0X0@ 0 0   0(` P@ 0 0  60 @@ 0 0  60 @ 0 0  60  @ 0 0  6x 8@ @ 0 0  6` @P @ 0 0  6G 0 @ 0 0  67 (H @ 0 0  6 0H @ 0 0B  s *޽h ? ̙33y___PPT10Y+D=' = @B + 0L0 ;(    0\Hx PBefore you start it would be helpful to& Recall the electronic configurations of the first 36 elements Recall the properties of the three main sub-atomic particlesH*(2 2)  0e _IONISATION ENERGY2(2(f<fdB  <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0B  s *޽h ? ̙33y___PPT10Y+D=' = @B + 0L0  e(    0 dWHAT IS IONISATION ENERGY?.(2f  B,̙))?: @Ionisation Energy is a measure of the amount of energy needed to remove electrons from atoms. As electrons are negatively charged and protons in the nucleus are positively charged, there will be an attraction between them. The greater the pull of the nucleus, the harder it will be to pull an electron away from an atom.A 2A 7/F :0P   xVR  C "A hgif:0P  0q A-$(2  0Т  f.Attraction between the nucleus and an electron/(2/dB   <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0B  s *޽h ? ̙33y___PPT10Y+D=' = @B +I 0L0 X P  ( w   0"` dWHAT IS IONISATION ENERGY?.(2f  B))?: @Ionisation Energy is a measure of the amount of energy needed to remove electrons from atoms. As electrons are negatively charged and protons in the nucleus are positively charged, there will be an attraction between them. The greater the pull of the nucleus, the harder it will be to pull an electron away from an atom.,A 2@ 7-8 :0P  xVX   S (A hgif:0P   6q A-$(2   0x  f.Attraction between the nucleus and an electron/(2/5  04Ģx  FIRST IONISATION ENERGY - Definition The energy required to remove ONE MOLE of electrons (to infinity) from ONE MOLE of gaseous atoms to form ONE MOLE of gaseous positive ions. e.g. Na(g) Na+(g) + e- Al(g) Al+(g) + e-t%(2 2$ %fff fffff fffffH     ) ^B  6D0  0 ^B  6D( (  Bע))? x vMake sure you write in the (g)<(2f^B  6D)dB  <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0B  s *޽h ? ̙33y___PPT10Y+D=' = @B +  0L0    (     0"` iWHAT AFFECTS IONISATION ENERGY?. (2f  0"`6  JThe value of the 1st Ionisation Energy depends on the electronic structureK(2K ,J  C "A hgif L  C $A hegifB @ L  C $A ligig  0j0pd DHydrogen (2 f  0 d BHelium (2f  0Pd CLithium (2f  NDT````?6  `The value for helium is higher than that for hydrogen because there are now two protons in the nucleus. The nuclear charge is greater so the pull on the outer electrons is larger. More energy will be needed to pull an electron out of the atom. P 21  0lT: n 519 kJ mol-1F (2 fff  0 T8p o 1310 kJ mol-1F(2 fff  0T8w   o 2370 kJ mol-1F(2 fffdB  <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0B  s *޽h ? ̙33y___PPT10Y+D=' = @B +) 0L0 80( w   0T iWHAT AFFECTS IONISATION ENERGY?. (2f  0T6  JThe value of the 1st Ionisation Energy depends on the electronic structureK(2K ,J  C "A hgif L  C $A hegifB @ L  C $A ligig  0%T0pd DHydrogen (2 f  0d)T d BHelium (2f   0|-TPd CLithium (2f   N0T````? xThe value for helium is higher than that for hydrogen because there are now two protons in the nucleus. The nuclear charge is greater so the pull on the outer electrons is larger. More energy will be needed to pull an electron out of the atom. Lithium atoms have 3 protons so you would expect the pull on electrons to be greater. However, the 1st Ionisation Energy of lithium is lower than that of helium because& Filled inner shells exert a SHIELDING EFFECT; lowers the effective nuclear pull FURTHER AWAY from the nucleus = lower nuclear attraction for an electron 20Z2 2c>'f% =\    0ET: n 519 kJ mol-1F (2 fff   0tKT8p o 1310 kJ mol-1F(2 fff   0OT8w   o 2370 kJ mol-1F(2 fffdB  <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0B  s *޽h ? ̙33y___PPT10Y+D=' = @B + 0L0 lX( w l l NA  3?))?`  Z l 0YT 1st Ionisation Energy shows a  general increase across a given period0G(2F 9  l <d`T"`h ,Variation in 1st Ionisation Energy - PERIODS -(2- dB  l <D)P0Q  l 0Pp@ 0 0dB  l@ <D)PXP  l 0X0@ 0 0B l s *޽h ? ̙33y___PPT10Y+D=' = @B +  0L0   n ( w 8 @  OP  <A G??@  G   0qT0P BHe$(2   0T T \Ne$(2  0` 4 \Ar$(2  0X  BKr$(2  0 \Xe$(2j  ZT````))?`?  V1st Ionisation Energy values show a periodic trend. There is a  general increase across a period before the value drops dramatically for the start of another period. The values get smaller down groups as the electron removed comes from an orbital further from the nucleus - there is more shielding.L, 22 dB  <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0  <pT"`h ,Variation in 1st Ionisation Energy - PERIODS -(2- B  s *޽h ? ̙33y___PPT10Y+D=' = @B +  0L0   h (  h h 0Z k GROUP I Value decreases down the Group despite an increased nuclear charge the outer s electron is easier to remove this is due to increased shielding and greater distance from the nucleus the outer electron is held less strongly and easier to remove.*ffff.0ffffS  L  h C $A krng1} N  h C &Alirng1*[ N  h C &Anarng1e o  h 0dTz CN  b 519 kJ mol-1: (2   h 0̳T >Li (2f h 0T u t  b 494 kJ mol-1: (2   h 08T @  b 418 kJ mol-1: (2   h 0T  >Na (2f h 0`T =K (2fdB h <D)P0Q h 0Pp@ 0 0dB h@ <D)PXP h 0X0@ 0 0 h <HT"`u +Variation in 1st Ionisation Energy - GROUPS ,(2, B h s *޽h ? ̙33y___PPT10Y+D=' = @B + 0L0   & ( \   0TZ k GROUP I Value decreases down the Group despite an increased nuclear charge the outer s electron is easier to remove this is due to increased shielding and greater distance from the nucleus the outer electron is held less strongly and easier to remove.*ffff.0ffffS  L  C $A krng1} N  C &Alirng1*[   0 T P GGROUP II Similar trend to Group I Group II values are greater than their Group I neighbours increased nuclear charge = stronger pull on electron more energy required to remove an electronF$ff N  C &Anarng1e o   0pTz CN  b 519 kJ mol-1: (2    0PT >Li (2f   0T u t  b 494 kJ mol-1: (2     0D @  b 418 kJ mol-1: (2     0  >Na (2f   0@  =K (2fdB   <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0  <Tu +Variation in 1st Ionisation Energy - GROUPS ,(2, B  s *޽h ? ̙33y___PPT10Y+D=' = @B + 0L0 0( w R2 ; s *>i^ z 61mi0L Zo {#  |ZfB | 6DjJoofB }B 6DjJZo0L Zo ~#  ZfB  6DjJoofB B 6DjJZo|L D  #  fB  6DjJ  D fB  6DjJ  fB  6DjJ fB  6DjJ  fB  6DjJ- - fB  6DjJ fB  6DjJ fB  6DjJfB  6DjJ fB  6DjJa afB  6DjJi ifB  6DjJ L  < Pb  #  J3fB  6DjJ > P> fB  6DjJ$B $b fB  6DjJ>B >b fB  6DjJ` B ` b fB  6DjJ@ B @ b fB  6DjJz ? z _ fB  6DjJ B b fB  6DjJ B b fB  6DjJ? b fB  6DjJ< _ fB  6DjJ? b fB  6DjJ? b fB  6DjJ? b   0 P] G ATOMIC NUMBER 2 f  6iR2  $ s *cLL Hr . -$# ` .$ 01) .8T Zo /$# fB 0$ 6DjJoofB 1$B 6DjJZo8T Zo 2$#   fB 3$ 6DjJoofB 4$B 6DjJZo 5$ 0JHr  L1s. 2 f f^ 7$ 61mi0L Zo 8$#  |ZfB 9$ 6DjJoofB :$B 6DjJZo0L Zo ;$#  ZfB <$ 6DjJoofB =$B 6DjJZo >$ 6P8 L1s. 2 f f|L D  ?$#  fB @$ 6DjJ  D fB A$ 6DjJ  fB B$ 6DjJ fB C$ 6DjJ  fB D$ 6DjJ- - fB E$ 6DjJ fB F$ 6DjJ fB G$ 6DjJfB H$ 6DjJ fB I$ 6DjJa afB J$ 6DjJi ifB K$ 6DjJ L  < Pb  L$#  J3fB M$ 6DjJ > P> fB N$ 6DjJ$B $b fB O$ 6DjJ>B >b fB P$ 6DjJ` B ` b fB Q$ 6DjJ@ B @ b fB R$ 6DjJz ? z _ fB S$ 6DjJ B b fB T$ 6DjJ B b fB U$ 6DjJ? b fB V$ 6DjJ< _ fB W$ 6DjJ? b fB X$ 6DjJ? b fB Y$ 6DjJ? b  Z$ 0] P] G ATOMIC NUMBER 2 f [$ 6a7n  t 1st IONISATION ENERGY / kJmol-18! 2     ]$ <g̙1?"`606 ;EXPLANATION Helium has a much higher value because of the extra proton in the nucleus. The additional charge provides a stronger attraction for the electrons making them harder to remove.d (2 2 f ^$ 0Hppw "Variation in 1st Ionisation Energy #(2# L `$ C $A hegif(0  a$ 0uB >HELIUM(2 b$ 0yJ E2((2dB c$ <D)P0Q d$ 0Pp@ 0 0dB e$@ <D)PXP f$ 0X0@ 0 0B $ s *޽h ? ̙33y___PPT10Y+D=' = @B +% 0L0 $$0Lh( )$(  (^B ( 6Do3^B ( 6Do%3W R2  ( s *f>iR2  ( s *fcLR2  ( s *5 l ^ ( 617 ` ^ ( 617 9 0L Zo  (# E  fB !( 6DjJoofB "(B 6DjJZo0L Zo #(# E ) fB $( 6DjJoofB %(B 6DjJZo0L Zo &(# E l fB '( 6DjJoofB ((B 6DjJZo0L Zo )(# E  fB *( 6DjJoofB +(B 6DjJZo ,( 6\ U  H1s 2s& 2  L Hr . -(# ` .( 01) .8T Zo /(# fB 0( 6DjJoofB 1(B 6DjJZo8T Zo 2(#   fB 3( 6DjJoofB 4(B 6DjJZo 5( 0@Hr  D1s& 2  ^ 7( 61mi0L Zo 8(#  |ZfB 9( 6DjJoofB :(B 6DjJZo0L Zo ;(#  ZfB <( 6DjJoofB =(B 6DjJZo >( 6ؙ8 D1s& 2  |L D  ?(#  fB @( 6DjJ  D fB A( 6DjJ  fB B( 6DjJ fB C( 6DjJ  fB D( 6DjJ- - fB E( 6DjJ fB F( 6DjJ fB G( 6DjJfB H( 6DjJ fB I( 6DjJa afB J( 6DjJi ifB K( 6DjJ L  < Pb  L(#  J3fB M( 6DjJ > P> fB N( 6DjJ$B $b fB O( 6DjJ>B >b fB P( 6DjJ` B ` b fB Q( 6DjJ@ B @ b fB R( 6DjJz ? z _ fB S( 6DjJ B b fB T( 6DjJ B b fB U( 6DjJ? b fB V( 6DjJ< _ fB W( 6DjJ? b fB X( 6DjJ? b fB Y( 6DjJ? b  Z( 0d P] C ATOMIC NUMBER 2  [( 6$8m  t 1st IONISATION ENERGY / kJmol-18! 2    | ]( <ܱ̙1?"`60F  EXPLANATION There is a substantial drop in the value for Lithium. This is because the extra electron has gone into an orbital in the next energy level. Despite the increased nuclear charge, the effective nuclear charge is less because of the shielding effect of filled inner 1s energy level. The 2s electron is also further away from the nucleus. It is held less strongly and needs less energy for removal.N (2 2 -Y ^( 08pw "Variation in 1st Ionisation Energy #(2# L `( C $A ligig(0  a( 0@“B ?LITHIUM(2 b( 0<ƓJ C3&(2dB c( <D)P0Q d( 0Pp@ 0 0dB e(@ <D)PXP f( 0X0@ 0 0B ( s *޽h ? ̙33y___PPT10Y+D=' = @B +* 0L0 ))@Zg0 )(  0^B 0 6Do3^B 0 6Do%3W ^B 0 6Do NDn R2  0 s *f>iR2  0 s *fcLR2  0 s *f5 l R2  0 s *I  L V l   0#  J ` 0 01  l l ` 0 01  l 8T Zo 0#   ] fB 0 6DjJoofB 0B 6DjJZo8T Zo 0#   ] fB 0 6DjJoofB 0B 6DjJZo8T Zo 0#   - ] fB 0 6DjJoofB 0B 6DjJZo8T Zo 0# D  Y ] fB 0 6DjJoofB 0B 6DjJZo 0 0דV  H1s 2s& 2  ^ 0 617 ` ^ 0 617 9 0L Zo  0# E  fB !0 6DjJoofB "0B 6DjJZo0L Zo #0# E ) fB $0 6DjJoofB %0B 6DjJZo0L Zo &0# E l fB '0 6DjJoofB (0B 6DjJZo0L Zo )0# E  fB *0 6DjJoofB +0B 6DjJZo ,0 6@ U  H1s 2s& 2  L Hr . -0# ` .0 01) .8T Zo /0# fB 00 6DjJoofB 10B 6DjJZo8T Zo 20#   fB 30 6DjJoofB 40B 6DjJZo 50 0|Hr  D1s& 2  ^ 70 61mi0L Zo 80#  |ZfB 90 6DjJoofB :0B 6DjJZo >0 68 D1s& 2  |L D  ?0#  fB @0 6DjJ  D fB A0 6DjJ  fB B0 6DjJ fB C0 6DjJ  fB D0 6DjJ- - fB E0 6DjJ fB F0 6DjJ fB G0 6DjJfB H0 6DjJ fB I0 6DjJa afB J0 6DjJi ifB K0 6DjJ L  < Pb  L0#  J3fB M0 6DjJ > P> fB N0 6DjJ$B $b fB O0 6DjJ>B >b fB P0 6DjJ` B ` b fB Q0 6DjJ@ B @ b fB R0 6DjJz ? z _ fB S0 6DjJ B b fB T0 6DjJ B b fB U0 6DjJ? b fB V0 6DjJ< _ fB W0 6DjJ? b fB X0 6DjJ? b fB Y0 6DjJ? b  Z0 0 P] C ATOMIC NUMBER 2  [0 68m  t 1st IONISATION ENERGY / kJmol-18! 2    W ]0 <4̙1?@   EXPLANATION The value for Beryllium is higher than for Lithium due to the increased nuclear charge. There is no extra shielding. N (2v 2  _ ^0 0pw "Variation in 1st Ionisation Energy #(2#  `0 0B A BERYLLIUM (2  a0 0J 94(2dB b0 <D)P0Q c0 0Pp@ 0 0dB d0@ <D)PXP e0 0X0@ 0 0z 0 bA޽h @ ?Parchment ̙33y___PPT10Y+D=' = @B +N5 0L0 ]4U4Pn0 3( w ^B 1 6Do3^B 2 6Do%3W ^B 3 6Do NDn ^B 4 6Do h: R2 ; s *f>iR2 < s *fcLR2 = s *f5 l R2 A s *fI  R2 B s * :- ^ , 61 J ^ - 61 ^ . 61 & ^ / 61 & ^ 0 61 # 0L Zo 1# % r fB 2 6DjJoofB 3B 6DjJZo0L Zo 4# % r fB 5 6DjJoofB 6B 6DjJZo0L Zo 7# % Vkr fB 8 6DjJoofB 9B 6DjJZo0L Zo :# % r fB ; 6DjJoofB <B 6DjJZo0L Zo =# % r fB > 6DjJoofB ?B 6DjJZo O 6;  5  P1s 2s 2p& 2  L V l  P#  J ` Q 01  l l ` R 01  l 8T Zo S#   ] fB T 6DjJoofB UB 6DjJZo8T Zo V#   ] fB W 6DjJoofB XB 6DjJZo8T Zo Y#   - ] fB Z 6DjJoofB [B 6DjJZo8T Zo \# D  Y ] fB ] 6DjJoofB ^B 6DjJZo _ 0?V  H1s 2s& 2  ^ a 617 ` ^ b 617 9 0L Zo c# E  fB d 6DjJoofB eB 6DjJZo0L Zo f# E ) fB g 6DjJoofB hB 6DjJZo0L Zo i# E l fB j 6DjJoofB kB 6DjJZo o 6( U  H1s 2s& 2  L Hr . p# ` q 01) .8T Zo r# fB s 6DjJoofB tB 6DjJZo8T Zo u#   fB v 6DjJoofB wB 6DjJZo x 0LHr  @1s" 2 ^ z 61mi0L Zo {#  |ZfB | 6DjJoofB }B 6DjJZo  6(W8 @1s" 2 |L D  #  fB  6DjJ  D fB  6DjJ  fB  6DjJ fB  6DjJ  fB  6DjJ- - fB  6DjJ fB  6DjJ fB  6DjJfB  6DjJ fB  6DjJa afB  6DjJi ifB  6DjJ L  < Pb  #  J3fB  6DjJ > P> fB  6DjJ$B $b fB  6DjJ>B >b fB  6DjJ` B ` b fB  6DjJ@ B @ b fB  6DjJz ? z _ fB  6DjJ B b fB  6DjJ B b fB  6DjJ? b fB  6DjJ< _ fB  6DjJ? b fB  6DjJ? b fB  6DjJ? b   0_ P] C ATOMIC NUMBER 2   6(  8^B 8 6Do3^B 8 6Do%3W ^B 8 6Do NDn ^B 8 6Do h: ^B  8 6DoQ d R2  8 s *f>iR2 8 s *fcLR2 8 s *f5 l R2 8 s * lu R2 8 s *fI  R2 8 s *f :- ^ 8 61e ^ 8 61Ne ^ 8 61e ^ 8 61.e ^ 8 61+e 0L Zo 8#  :OV fB 8 6DjJoofB 8B 6DjJZo0L Zo 8#  f{V fB 8 6DjJoofB 8B 6DjJZo0L Zo 8#  V fB 8 6DjJoofB 8B 6DjJZo0L Zo 8#  V fB 8 6DjJoofB 8B 6DjJZo0L Zo 8#  <QV fB 8 6DjJoofB 8B 6DjJZo0L Zo 8#  V fB 8 6DjJoofB 8B 6DjJZo 8 6䐕<  P1s 2s 2p& 2  ^ 8 61 J ^ 8 61 ^ 8 61 & ^ 8 61 & ^ 8 61 # 0L Zo 8# % r fB 8 6DjJoofB 8B 6DjJZo0L Zo 8# % r fB 8 6DjJoofB 8B 6DjJZo0L Zo 8# % Vkr fB 8 6DjJoofB 8B 6DjJZo0L Zo 8# % r fB 8 6DjJoofB 8B 6DjJZo0L Zo 8# % r fB 8 6DjJoofB 8B 6DjJZo 8 6  5  P1s 2s 2p& 2  L V l  8#  J ` 8 01  l l ` 8 01  l 8T Zo 8#   ] fB 8 6DjJoofB 8B 6DjJZo8T Zo 8#   ] fB 8 6DjJoofB 8B 6DjJZo8T Zo 8#   - ] fB 8 6DjJoofB 8B 6DjJZo8T Zo 9# D  Y ] fB 9 6DjJoofB 9B 6DjJZo 9 0hV  H1s 2s& 2  ^ 9 617 ` ^ 9 617 9 0L Zo 9# E  fB 9 6DjJoofB  9B 6DjJZo0L Zo  9# E ) fB  9 6DjJoofB  9B 6DjJZo0L Zo  9# E l fB 9 6DjJoofB 9B 6DjJZo 9 64 U  H1s 2s& 2  L Hr . 9# ` 9 01) .8T Zo 9# fB 9 6DjJoofB 9B 6DjJZo8T Zo 9#   fB 9 6DjJoofB 9B 6DjJZo 9 0Hr  @1s" 2 ^ 9 61mi0L Zo 9#  |ZfB  9 6DjJoofB !9B 6DjJZo %9 6̷8 @1s" 2 |L D  &9#  fB '9 6DjJ  D fB (9 6DjJ  fB )9 6DjJ fB *9 6DjJ  fB +9 6DjJ- - fB ,9 6DjJ fB -9 6DjJ fB .9 6DjJfB /9 6DjJ fB 09 6DjJa afB 19 6DjJi ifB 29 6DjJ L  < Pb  39#  J3fB 49 6DjJ > P> fB 59 6DjJ$B $b fB 69 6DjJ>B >b fB 79 6DjJ` B ` b fB 89 6DjJ@ B @ b fB 99 6DjJz ? z _ fB :9 6DjJ B b fB ;9 6DjJ B b fB <9 6DjJ? b fB =9 6DjJ< _ fB >9 6DjJ? b fB ?9 6DjJ? b fB @9 6DjJ? b  C9 00ĕ P] C ATOMIC NUMBER 2  D9 6ȕ8m  t 1st IONISATION ENERGY / kJmol-18! 2     G9 0͕pw "Variation in 1st Ionisation Energy #(2#  H9 <hҕ̙1?@ x  rEXPLANATION The value increases again for Carbon due to the increased nuclear charge. The extra electron does not pair up with the previous one in the same orbital but occupies another of the 2p orbitals. This gives a lower energy configuration because there is less repulsion between the negatively charged particles. This is known as Hund s Rule.h (2R 2   , I9 0ߕB >CARBON(2 J9 0J(  96(2dB K9 <D)P0Q L9 0Pp@ 0 0dB M9@ <D)PXP N9 0X0@ 0 0B 8 s *޽h ? ̙33y___PPT10Y+D=' = @B +I 0L0 IHpR=P}H( w <^B < 6Do3^B < 6Do%3W ^B < 6Do NDn ^B < 6Do h: ^B  < 6DoQ d ^B  < 6Do K R2  < s *f>iR2 < s *fcLR2 < s *f5 l R2 < s *b R2 < s *f lu R2 < s *fI  R2 < s *f :- ^ < 61{^ < 61{8 ^ < 61{x^ < 61{x^ < 61{u0L Zo <# $9fB < 6DjJoofB <B 6DjJZo0L Zo <# PefB < 6DjJoofB <B 6DjJZo0L Zo <# fB < 6DjJoofB <B 6DjJZo0L Zo <# fB < 6DjJoofB <B 6DjJZo0L Zo <# &;fB < 6DjJoofB <B 6DjJZo0L Zo <# fB < 6DjJoofB <B 6DjJZo0L Zo <# fB < 6DjJoofB <B 6DjJZo < 6d&  P1s 2s 2p& 2  ^ < 61e ^ < 61Ne ^ < 61e ^ < 61.e ^ < 61+e 0L Zo <#  :OV fB < 6DjJoofB <B 6DjJZo0L Zo <#  f{V fB < 6DjJoofB <B 6DjJZo0L Zo <#  V fB < 6DjJoofB <B 6DjJZo0L Zo <#  V fB < 6DjJoofB <B 6DjJZo0L Zo <#  <QV fB < 6DjJoofB <B 6DjJZo0L Zo <#  V fB < 6DjJoofB <B 6DjJZo < 6,<  P1s 2s 2p& 2  ^ < 61 J ^ < 61 ^ < 61 & ^ < 61 & ^ < 61 # 0L Zo <# % r fB < 6DjJoofB <B 6DjJZo0L Zo <# % r fB < 6DjJoofB <B 6DjJZo0L Zo <# % Vkr fB < 6DjJoofB <B 6DjJZo0L Zo <# % r fB < 6DjJoofB <B 6DjJZo0L Zo <# % r fB < 6DjJoofB <B 6DjJZo < 6  5  P1s 2s 2p& 2  L V l  <#  J ` < 01  l l ` < 01  l 8T Zo <#   ] fB < 6DjJoofB <B 6DjJZo8T Zo <#   ] fB < 6DjJoofB <B 6DjJZo8T Zo <#   - ] fB < 6DjJoofB <B 6DjJZo8T Zo =# D  Y ] fB = 6DjJoofB =B 6DjJZo = 0DV  H1s 2s& 2  ^ = 617 ` ^ = 617 9 0L Zo =# E  fB = 6DjJoofB  =B 6DjJZo0L Zo  =# E ) fB  = 6DjJoofB  =B 6DjJZo0L Zo  =# E l fB = 6DjJoofB =B 6DjJZo = 6 " U  H1s 2s& 2  L Hr . =# ` = 01) .8T Zo =# fB = 6DjJoofB =B 6DjJZo8T Zo =#   fB = 6DjJoofB =B 6DjJZo = 0)Hr  D1s& 2  ^ = 61mi0L Zo =#  |ZfB  = 6DjJoofB !=B 6DjJZo %= 6.8 D1s& 2  |L D  &=#  fB '= 6DjJ  D fB (= 6DjJ  fB )= 6DjJ fB *= 6DjJ  fB += 6DjJ- - fB ,= 6DjJ fB -= 6DjJ fB .= 6DjJfB /= 6DjJ fB 0= 6DjJa afB 1= 6DjJi ifB 2= 6DjJ L  < Pb  3=#  J3fB 4= 6DjJ > P> fB 5= 6DjJ$B $b fB 6= 6DjJ>B >b fB 7= 6DjJ` B ` b fB 8= 6DjJ@ B @ b fB 9= 6DjJz ? z _ fB := 6DjJ B b fB ;= 6DjJ B b fB <= 6DjJ? b fB == 6DjJ< _ fB >= 6DjJ? b fB ?= 6DjJ? b fB @= 6DjJ? b  C= 0: P] C ATOMIC NUMBER 2  D= 6?8m  t 1st IONISATION ENERGY / kJmol-18! 2     G= 0DEpw "Variation in 1st Ionisation Energy #(2#  J= <I̙1?@  )EXPLANATION The value increases again for Nitrogen due to the increased nuclear charge. As before, the extra electron goes into the vacant 2p orbital. There are now three unpaired electrons.N (2 2   K= 0iR2 @ s *fcLR2 @ s *f5 l R2 @ s * s oR2 @ s *fb R2 @ s *f lu R2 @ s *fI  R2 @ s *f :- ^ a@ 61S ^ b@ 61S . ^ c@ 61Sn ^ d@ 61S n ^ e@ 61S k 0L Zo f@# a / fB g@ 6DjJoofB h@B 6DjJZo0L Zo i@# aF [ fB j@ 6DjJoofB k@B 6DjJZo0L Zo l@# a fB m@ 6DjJoofB n@B 6DjJZo0L Zo o@# a fB p@ 6DjJoofB q@B 6DjJZo0L Zo r@# a 1 fB s@ 6DjJoofB t@B 6DjJZo0L Zo u@# aH ] fB v@ 6DjJoofB w@B 6DjJZo0L Zo x@# a| fB y@ 6DjJoofB z@B 6DjJZo0L Zo ~@# c fB @ 6DjJoofB @B 6DjJZo @ 6\m  q P1s 2s 2p& 2  ^ @ 61{^ @ 61{8 ^ @ 61{x^ @ 61{x^ @ 61{u0L Zo @# $9fB @ 6DjJoofB @B 6DjJZo0L Zo @# PefB @ 6DjJoofB @B 6DjJZo0L Zo @# fB @ 6DjJoofB @B 6DjJZo0L Zo @# fB @ 6DjJoofB @B 6DjJZo0L Zo @# &;fB @ 6DjJoofB @B 6DjJZo0L Zo @# fB @ 6DjJoofB @B 6DjJZo0L Zo @# fB @ 6DjJoofB @B 6DjJZo @ 6Tz&  P1s 2s 2p& 2  ^ @ 61e ^ @ 61Ne ^ @ 61e ^ @ 61.e ^ @ 61+e 0L Zo @#  :OV fB @ 6DjJoofB @B 6DjJZo0L Zo @#  f{V fB @ 6DjJoofB @B 6DjJZo0L Zo @#  V fB @ 6DjJoofB @B 6DjJZo0L Zo @#  V fB @ 6DjJoofB @B 6DjJZo0L Zo @#  <QV fB @ 6DjJoofB @B 6DjJZo0L Zo @#  V fB @ 6DjJoofB @B 6DjJZo @ 6<  P1s 2s 2p& 2  ^ @ 61 J ^ @ 61 ^ @ 61 & ^ @ 61 & ^ @ 61 # 0L Zo @# % r fB @ 6DjJoofB @B 6DjJZo0L Zo @# % r fB @ 6DjJoofB @B 6DjJZo0L Zo @# % Vkr fB @ 6DjJoofB @B 6DjJZo0L Zo @# % r fB @ 6DjJoofB @B 6DjJZo0L Zo @# % r fB @ 6DjJoofB @B 6DjJZo @ 6  5  P1s 2s 2p& 2  L V l  @#  J ` @ 01  l l ` @ 01  l 8T Zo @#   ] fB @ 6DjJoofB @B 6DjJZo8T Zo @#   ] fB @ 6DjJoofB @B 6DjJZo8T Zo @#   - ] fB @ 6DjJoofB @B 6DjJZo8T Zo A# D  Y ] fB A 6DjJoofB AB 6DjJZo A 0ЛV  H1s 2s& 2  ^ A 617 ` ^ A 617 9 0L Zo A# E  fB A 6DjJoofB  AB 6DjJZo0L Zo  A# E ) fB  A 6DjJoofB  AB 6DjJZo0L Zo  A# E l fB A 6DjJoofB AB 6DjJZo A 6t U  H1s 2s& 2  L Hr . A# ` A 01) .8T Zo A# fB A 6DjJoofB AB 6DjJZo8T Zo A#   fB A 6DjJoofB AB 6DjJZo A 0XHr  D1s& 2  ^ A 61mi0L Zo A#  |ZfB  A 6DjJoofB !AB 6DjJZo %A 68 D1s& 2  |L D  &A#  fB 'A 6DjJ  D fB (A 6DjJ  fB )A 6DjJ fB *A 6DjJ  fB +A 6DjJ- - fB ,A 6DjJ fB -A 6DjJ fB .A 6DjJfB /A 6DjJ fB 0A 6DjJa afB 1A 6DjJi ifB 2A 6DjJ L  < Pb  3A#  J3fB 4A 6DjJ > P> fB 5A 6DjJ$B $b fB 6A 6DjJ>B >b fB 7A 6DjJ` B ` b fB 8A 6DjJ@ B @ b fB 9A 6DjJz ? z _ fB :A 6DjJ B b fB ;A 6DjJ B b fB A 6DjJ? b fB ?A 6DjJ? b fB @A 6DjJ? b  CA 0 P] C ATOMIC NUMBER 2  DA 68m  t 1st IONISATION ENERGY / kJmol-18! 2     GA 0ƛpw "Variation in 1st Ionisation Energy #(2# ; HA <ʛ̙1?@  EXPLANATION There is a DROP in the value for Oxygen. The extra electron has paired up with one of the electrons already in one of the 2p orbitals. The repulsive force beteen the two paired-up electrons means that less energy is required to remove one of them.| (2 2  f,W IA 0؛B >OXYGEN(2 JA 0 ܛJ8 -  98(2dB KA <D)P0Q LA 0Pp@ 0 0dB MA@ <D)PXP NA 0X0@ 0 0B @ s *޽h ? ̙33y___PPT10Y+D=' = @B +e 0L0 ddQIp d( w H^B H 6Do3^B H 6Do%3W ^B H 6Do NDn ^B H 6Do h: ^B  H 6DoQ d ^B  H 6Do K ^B  H 6Do E^B  H 6Do8 ?R2  H s *f>iR2 H s *fcLR2 H s *f5 l R2 H s *f s oR2 H s *fb R2 H s *f lu R2 H s *fI  R2 H s *f :- R2 H s * ^ H 61 k^ ?H 61. k^ @H 61+ k0L Zo AH# : O \fB BH 6DjJoofB CHB 6DjJZo0L Zo DH# f { \fB EH 6DjJoofB FHB 6DjJZo0L Zo GH#  \fB HH 6DjJoofB IHB 6DjJZo0L Zo JH#  \fB KH 6DjJoofB LHB 6DjJZo0L Zo MH# < Q \fB NH 6DjJoofB OHB 6DjJZo0L Zo PH# h } \fB QH 6DjJoofB RHB 6DjJZo0L Zo SH#  \fB TH 6DjJoofB UHB 6DjJZo0L Zo VH#  \fB WH 6DjJoofB XHB 6DjJZo0L Zo YH#   ^fB ZH 6DjJoofB [HB 6DjJZo _H 6<  P1s 2s 2p& 2  ^ aH 61S ^ bH 61S . ^ cH 61Sn ^ dH 61S n ^ eH 61S k 0L Zo fH# a / fB gH 6DjJoofB hHB 6DjJZo0L Zo iH# aF [ fB jH 6DjJoofB kHB 6DjJZo0L Zo lH# a fB mH 6DjJoofB nHB 6DjJZo0L Zo oH# a fB pH 6DjJoofB qHB 6DjJZo0L Zo rH# a 1 fB sH 6DjJoofB tHB 6DjJZo0L Zo uH# aH ] fB vH 6DjJoofB wHB 6DjJZo0L Zo xH# a| fB yH 6DjJoofB zHB 6DjJZo0L Zo ~H# c fB H 6DjJoofB HB 6DjJZo H 6D  q P1s 2s 2p& 2  ^ H 61{^ H 61{8 ^ H 61{x^ H 61{x^ H 61{u0L Zo H# $9fB H 6DjJoofB HB 6DjJZo0L Zo H# PefB H 6DjJoofB HB 6DjJZo0L Zo H# fB H 6DjJoofB HB 6DjJZo0L Zo H# fB H 6DjJoofB HB 6DjJZo0L Zo H# &;fB H 6DjJoofB HB 6DjJZo0L Zo H# fB H 6DjJoofB HB 6DjJZo0L Zo H# fB H 6DjJoofB HB 6DjJZo H 6d&  P1s 2s 2p& 2  ^ H 61e ^ H 61Ne ^ H 61e ^ H 61.e ^ H 61+e 0L Zo H#  :OV fB H 6DjJoofB HB 6DjJZo0L Zo H#  f{V fB H 6DjJoofB HB 6DjJZo0L Zo H#  V fB H 6DjJoofB HB 6DjJZo0L Zo H#  V fB H 6DjJoofB HB 6DjJZo0L Zo H#  <QV fB H 6DjJoofB HB 6DjJZo0L Zo H#  V fB H 6DjJoofB HB 6DjJZo H 6`<  P1s 2s 2p& 2  ^ H 61 J ^ H 61 ^ H 61 & ^ H 61 & ^ H 61 # 0L Zo H# % r fB H 6DjJoofB HB 6DjJZo0L Zo H# % r fB H 6DjJoofB HB 6DjJZo0L Zo H# % Vkr fB H 6DjJoofB HB 6DjJZo0L Zo H# % r fB H 6DjJoofB HB 6DjJZo0L Zo H# % r fB H 6DjJoofB HB 6DjJZo H 6&  5  P1s 2s 2p& 2  L V l  H#  J ` H 01  l l ` H 01  l 8T Zo H#   ] fB H 6DjJoofB HB 6DjJZo8T Zo H#   ] fB H 6DjJoofB HB 6DjJZo8T Zo H#   - ] fB H 6DjJoofB HB 6DjJZo8T Zo I# D  Y ] fB I 6DjJoofB IB 6DjJZo I 0x0V  H1s 2s& 2  ^ I 617 ` ^ I 617 9 0L Zo I# E  fB I 6DjJoofB  IB 6DjJZo0L Zo  I# E ) fB  I 6DjJoofB  IB 6DjJZo0L Zo  I# E l fB I 6DjJoofB IB 6DjJZo I 6T8 U  H1s 2s& 2  L Hr . I# ` I 01) .8T Zo I# fB I 6DjJoofB IB 6DjJZo8T Zo I#   fB I 6DjJoofB IB 6DjJZo I 08?Hr  D1s& 2  ^ I 61mi0L Zo I#  |ZfB  I 6DjJoofB !IB 6DjJZo %I 6D8 D1s& 2  |L D  &I#  fB 'I 6DjJ  D fB (I 6DjJ  fB )I 6DjJ fB *I 6DjJ  fB +I 6DjJ- - fB ,I 6DjJ fB -I 6DjJ fB .I 6DjJfB /I 6DjJ fB 0I 6DjJa afB 1I 6DjJi ifB 2I 6DjJ L  < Pb  3I#  J3fB 4I 6DjJ > P> fB 5I 6DjJ$B $b fB 6I 6DjJ>B >b fB 7I 6DjJ` B ` b fB 8I 6DjJ@ B @ b fB 9I 6DjJz ? z _ fB :I 6DjJ B b fB ;I 6DjJ B b fB I 6DjJ? b fB ?I 6DjJ? b fB @I 6DjJ? b  CI 0P P] C ATOMIC NUMBER 2  DI 6U8m  t 1st IONISATION ENERGY / kJmol-18! 2     GI 0x[pw "Variation in 1st Ionisation Energy #(2# r II <_̙1?@ h zEXPLANATION The value increases again for Fluorine due to the increased nuclear charge. The 2p orbitals are almost full. N (2o 2  H_ JI 0hB @FLUORINE (2  KI 0lJ` U  99(2dB LI <D)P0Q MI 0Pp@ 0 0dB NI@ <D)PXP OI 0X0@ 0 0B H s *޽h ? ̙33y___PPT10Y+D=' = @B ++v 0L0 :u2uRQpt( w P^B P 6Do3^B P 6Do%3W ^B P 6Do NDn ^B P 6Do h: ^B  P 6DoQ d ^B  P 6Do K ^B  P 6Do E^B  P 6Do8 ?R2  P s *f>iR2 P s *fcLR2 P s *f5 l R2 P s *f s oR2 P s *fb R2 P s *f lu R2 P s *fI  R2 P s *f :- L  Df P# Q > 7` P 01f` P 01Df` P 01f` P 01$f` P 01!f8T Zo P# 0 EWfB P 6DjJoofB PB 6DjJZo8T Zo P# \ qWfB  P 6DjJoofB !PB 6DjJZo8T Zo "P#  WfB #P 6DjJoofB $PB 6DjJZo8T Zo %P#  WfB &P 6DjJoofB 'PB 6DjJZo8T Zo (P# 2 GWfB )P 6DjJoofB *PB 6DjJZo8T Zo +P# ^ sWfB ,P 6DjJoofB -PB 6DjJZo8T Zo .P#  WfB /P 6DjJoofB 0PB 6DjJZo8T Zo 1P#  WfB 2P 6DjJoofB 3PB 6DjJZo8T Zo 4P#  YfB 5P 6DjJoofB 6PB 6DjJZo8T Zo 7P#  1YfB 8P 6DjJoofB 9PB 6DjJZo :P 0 2 P1s 2s 2p& 2  ^ P 61 k^ ?P 61. k^ @P 61+ k0L Zo AP# : O \fB BP 6DjJoofB CPB 6DjJZo0L Zo DP# f { \fB EP 6DjJoofB FPB 6DjJZo0L Zo GP#  \fB HP 6DjJoofB IPB 6DjJZo0L Zo JP#  \fB KP 6DjJoofB LPB 6DjJZo0L Zo MP# < Q \fB NP 6DjJoofB OPB 6DjJZo0L Zo PP# h } \fB QP 6DjJoofB RPB 6DjJZo0L Zo SP#  \fB TP 6DjJoofB UPB 6DjJZo0L Zo VP#  \fB WP 6DjJoofB XPB 6DjJZo0L Zo YP#   ^fB ZP 6DjJoofB [PB 6DjJZo _P 6|<  P1s 2s 2p& 2  ^ aP 61S ^ bP 61S . ^ cP 61Sn ^ dP 61S n ^ eP 61S k 0L Zo fP# a / fB gP 6DjJoofB hPB 6DjJZo0L Zo iP# aF [ fB jP 6DjJoofB kPB 6DjJZo0L Zo lP# a fB mP 6DjJoofB nPB 6DjJZo0L Zo oP# a fB pP 6DjJoofB qPB 6DjJZo0L Zo rP# a 1 fB sP 6DjJoofB tPB 6DjJZo0L Zo uP# aH ] fB vP 6DjJoofB wPB 6DjJZo0L Zo xP# a| fB yP 6DjJoofB zPB 6DjJZo0L Zo ~P# c fB P 6DjJoofB PB 6DjJZo P 6  q P1s 2s 2p& 2  ^ P 61{^ P 61{8 ^ P 61{x^ P 61{x^ P 61{u0L Zo P# $9fB P 6DjJoofB PB 6DjJZo0L Zo P# PefB P 6DjJoofB PB 6DjJZo0L Zo P# fB P 6DjJoofB PB 6DjJZo0L Zo P# fB P 6DjJoofB PB 6DjJZo0L Zo P# &;fB P 6DjJoofB PB 6DjJZo0L Zo P# fB P 6DjJoofB PB 6DjJZo0L Zo P# fB P 6DjJoofB PB 6DjJZo P 6&  P1s 2s 2p& 2  ^ P 61e ^ P 61Ne ^ P 61e ^ P 61.e ^ P 61+e 0L Zo P#  :OV fB P 6DjJoofB PB 6DjJZo0L Zo P#  f{V fB P 6DjJoofB PB 6DjJZo0L Zo P#  V fB P 6DjJoofB PB 6DjJZo0L Zo P#  V fB P 6DjJoofB PB 6DjJZo0L Zo P#  <QV fB P 6DjJoofB PB 6DjJZo0L Zo P#  V fB P 6DjJoofB PB 6DjJZo P 6@<  P1s 2s 2p& 2  ^ P 61 J ^ P 61 ^ P 61 & ^ P 61 & ^ P 61 # 0L Zo P# % r fB P 6DjJoofB PB 6DjJZo0L Zo P# % r fB P 6DjJoofB PB 6DjJZo0L Zo P# % Vkr fB P 6DjJoofB PB 6DjJZo0L Zo P# % r fB P 6DjJoofB PB 6DjJZo0L Zo P# % r fB P 6DjJoofB PB 6DjJZo P 6Ř  5  P1s 2s 2p& 2  L V l  P#  J ` P 01  l l ` P 01  l 8T Zo P#   ] fB P 6DjJoofB PB 6DjJZo8T Zo P#   ] fB P 6DjJoofB PB 6DjJZo8T Zo P#   - ] fB P 6DjJoofB PB 6DjJZo8T Zo Q# D  Y ] fB Q 6DjJoofB QB 6DjJZo Q 0XϘV  H1s 2s& 2  ^ Q 617 ` ^ Q 617 9 0L Zo Q# E  fB Q 6DjJoofB  QB 6DjJZo0L Zo  Q# E ) fB  Q 6DjJoofB  QB 6DjJZo0L Zo  Q# E l fB Q 6DjJoofB QB 6DjJZo Q 64ט U  H1s 2s& 2  L Hr . Q# ` Q 01) .8T Zo Q# fB Q 6DjJoofB QB 6DjJZo8T Zo Q#   fB Q 6DjJoofB QB 6DjJZo Q 0ޘHr  D1s& 2  ^ Q 61mi0L Zo Q#  |ZfB  Q 6DjJoofB !QB 6DjJZo %Q 68 D1s& 2  |L D  &Q#  fB 'Q 6DjJ  D fB (Q 6DjJ  fB )Q 6DjJ fB *Q 6DjJ  fB +Q 6DjJ- - fB ,Q 6DjJ fB -Q 6DjJ fB .Q 6DjJfB /Q 6DjJ fB 0Q 6DjJa afB 1Q 6DjJi ifB 2Q 6DjJ L  < Pb  3Q#  J3fB 4Q 6DjJ > P> fB 5Q 6DjJ$B $b fB 6Q 6DjJ>B >b fB 7Q 6DjJ` B ` b fB 8Q 6DjJ@ B @ b fB 9Q 6DjJz ? z _ fB :Q 6DjJ B b fB ;Q 6DjJ B b fB Q 6DjJ? b fB ?Q 6DjJ? b fB @Q 6DjJ? b ^B AQ 6DoH OR2 BQ s * v CQ 0t P] C ATOMIC NUMBER 2  DQ 6t8m  t 1st IONISATION ENERGY / kJmol-18! 2    R2 P s *f  GQ 0pw "Variation in 1st Ionisation Energy #(2#  JQ <̙1??  GEXPLANATION The value increases again for Neon due to the increased nuclear charge. The 2p orbitals are now full so the next electron in will have to go into the higher energy 3s orbital.N (2 2 [Y KQ 0 B <NEON(2 LQ 0Jh |  :10(2dB MQ <D)P0Q NQ 0Pp@ 0 0dB OQ@ <D)PXP PQ 0X0@ 0 0B P s *޽h ? ̙33y___PPT10Y+D=' = @B + 0L0 9E]( X  \^B \ 6Do3^B \ 6Do%3W ^B \ 6Do NDn ^B \ 6Do h: ^B  \ 6DoQ d ^B  \ 6Do K ^B  \ 6Do E^B  \ 6Do8 ?R2  \ s *f>iR2 \ s *fcLR2 \ s *f5 l R2 \ s *f s oR2 \ s *fb R2 \ s *f lu R2 \ s *fI  R2 \ s *f :- L  Df \# Q > 7` \ 01f` \ 01Df` \ 01f` \ 01$f` \ 01!f8T Zo \# 0 EWfB \ 6DjJoofB \B 6DjJZo8T Zo \# \ qWfB \ 6DjJoofB  \B 6DjJZo8T Zo !\#  WfB "\ 6DjJoofB #\B 6DjJZo8T Zo $\#  WfB %\ 6DjJoofB &\B 6DjJZo8T Zo '\# 2 GWfB (\ 6DjJoofB )\B 6DjJZo8T Zo *\# ^ sWfB +\ 6DjJoofB ,\B 6DjJZo8T Zo -\#  WfB .\ 6DjJoofB /\B 6DjJZo8T Zo 0\#  WfB 1\ 6DjJoofB 2\B 6DjJZo8T Zo 3\#  YfB 4\ 6DjJoofB 5\B 6DjJZo8T Zo 6\#  1YfB 7\ 6DjJoofB 8\B 6DjJZo 9\ 0l' 2 P1s 2s 2p& 2  X :\ 01  kX ;\ 01 N kX <\ 01 kX =\ 01. kX >\ 01+ k0L Zo ?\# : O \fB @\ 6DjJoofB A\B 6DjJZo0L Zo B\# f { \fB C\ 6DjJoofB D\B 6DjJZo0L Zo E\#  \fB F\ 6DjJoofB G\B 6DjJZo0L Zo H\#  \fB I\ 6DjJoofB J\B 6DjJZo0L Zo K\# < Q \fB L\ 6DjJoofB M\B 6DjJZo0L Zo N\# h } \fB O\ 6DjJoofB P\B 6DjJZo0L Zo Q\#  \fB R\ 6DjJoofB S\B 6DjJZo0L Zo T\#  \fB U\ 6DjJoofB V\B 6DjJZo0L Zo W\#   ^fB X\ 6DjJoofB Y\B 6DjJZo Z\ 0T6<  D1s 2s 2p 2 X [\ 01S X \\ 01S . X ]\ 01Sn X ^\ 01S n X _\ 01S k 0L Zo `\# a / fB a\ 6DjJoofB b\B 6DjJZo0L Zo c\# aF [ fB d\ 6DjJoofB e\B 6DjJZo0L Zo f\# a fB g\ 6DjJoofB h\B 6DjJZo0L Zo i\# a fB j\ 6DjJoofB k\B 6DjJZo0L Zo l\# a 1 fB m\ 6DjJoofB n\B 6DjJZo0L Zo o\# aH ] fB p\ 6DjJoofB q\B 6DjJZo0L Zo r\# a| fB s\ 6DjJoofB t\B 6DjJZo0L Zo u\# c fB v\ 6DjJoofB w\B 6DjJZo x\ 0C  q D1s 2s 2p 2 X y\ 01{X z\ 01{8 X {\ 01{xX |\ 01{xX }\ 01{u0L Zo ~\# $9fB \ 6DjJoofB \B 6DjJZo0L Zo \# PefB \ 6DjJoofB \B 6DjJZo0L Zo \# fB \ 6DjJoofB \B 6DjJZo0L Zo \# fB \ 6DjJoofB \B 6DjJZo0L Zo \# &;fB \ 6DjJoofB \B 6DjJZo0L Zo \# fB \ 6DjJoofB \B 6DjJZo0L Zo \# fB \ 6DjJoofB \B 6DjJZo \ 0O&  D1s 2s 2p 2 X \ 01e X \ 01Ne X \ 01e X \ 01.e X \ 01+e 0L Zo \#  :OV fB \ 6DjJoofB \B 6DjJZo0L Zo \#  f{V fB \ 6DjJoofB \B 6DjJZo0L Zo \#  V fB \ 6DjJoofB \B 6DjJZo0L Zo \#  V fB \ 6DjJoofB \B 6DjJZo0L Zo \#  <QV fB \ 6DjJoofB \B 6DjJZo0L Zo \#  V fB \ 6DjJoofB \B 6DjJZo \ 0([<  D1s 2s 2p 2 X \ 01 J X \ 01 X \ 01 & X \ 01 & X \ 01 # 0L Zo \# % r fB \ 6DjJoofB \B 6DjJZo0L Zo \# % r fB \ 6DjJoofB \B 6DjJZo0L Zo \# % Vkr fB \ 6DjJoofB \B 6DjJZo0L Zo \# % r fB \ 6DjJoofB \B 6DjJZo0L Zo \# % r fB \ 6DjJoofB \B 6DjJZo \ 0e  5  D1s 2s 2p 2 L V l  \#  J ` \ 01  l l ` \ 01  l 8T Zo \#   ] fB \ 6DjJoofB \B 6DjJZo8T Zo \#   ] fB \ 6DjJoofB \B 6DjJZo8T Zo \#   - ] fB \ 6DjJoofB \B 6DjJZo8T Zo \# D  Y ] fB \ 6DjJoofB \B 6DjJZo \ 0nV  <1s 2s 2 X \ 017 ` X \ 017 9 0L Zo \# E  fB \ 6DjJoofB \B 6DjJZo0L Zo \# E ) fB \ 6DjJoofB \B 6DjJZo0L Zo \# E l fB \ 6DjJoofB \B 6DjJZo \ 0u U  <1s 2s 2 L Hr . \# ` \ 01) .8T Zo \# fB \ 6DjJoofB \B 6DjJZo8T Zo \#   fB \ 6DjJoofB \B 6DjJZo \ 0{Hr  D1s& 2  X \ 01mi0L Zo \#  |ZfB \ 6DjJoofB \B 6DjJZo \ 0$8 81s 2 |L D  \#  fB \ 6DjJ  D fB \ 6DjJ  fB \ 6DjJ fB \ 6DjJ  fB \ 6DjJ- - fB \ 6DjJ fB \ 6DjJ fB \ 6DjJfB \ 6DjJ fB \ 6DjJa afB \ 6DjJi ifB \ 6DjJ L  < Pb  \#  J3fB \ 6DjJ > P> fB \ 6DjJ$B $b fB \ 6DjJ>B >b fB \ 6DjJ` B ` b fB \ 6DjJ@ B @ b fB \ 6DjJz ? z _ fB \ 6DjJ B b fB ] 6DjJ B b fB ] 6DjJ? b fB ] 6DjJ< _ fB ] 6DjJ? b fB ] 6DjJ? b fB ] 6DjJ? b ^B ] 6DoH O ] 0̌ P] C ATOMIC NUMBER 2   ] 6̑8m  t 1st IONISATION ENERGY / kJmol-18! 2    R2  ] s *f ^B  ] 6Do= R2 ] s * = ^ ] 61 8  ^ ] 61 t  ^ ] 61  t  ^ ] 61   ^ ] 61   ^ ] 61 X  0L Zo ]#   fB ] 6DjJoofB ]B 6DjJZo0L Zo ]#    fB ] 6DjJoofB ]B 6DjJZo0L Zo ]#  D Y  fB ] 6DjJoofB ]B 6DjJZo0L Zo ]#  p  fB  ] 6DjJoofB !]B 6DjJZo0L Zo "]#   fB #] 6DjJoofB $]B 6DjJZo0L Zo %]#    fB &] 6DjJoofB ']B 6DjJZo0L Zo (]#  " 7  fB )] 6DjJoofB *]B 6DjJZo0L Zo +]#  N c  fB ,] 6DjJoofB -]B 6DjJZo0L Zo .]#   fB /] 6DjJoofB 0]B 6DjJZo0L Zo 1]#   fB 2] 6DjJoofB 3]B 6DjJZo0L Zo 4]#     fB 5] 6DjJoofB 6]B 6DjJZo :] 69  Q1s 2s 2p 3s  2 R2 ] s *f v ;] 0pw "Variation in 1st Ionisation Energy #(2#  =] <0̙1?@   /EXPLANATION There is a substantial drop in the value for Sodium. This is because the extra electron has gone into an orbital in the next energy level. Despite the increased nuclear charge, the effective nuclear charge is less because of the shielding effect of filled inner 1s, 2s and 2p energy levels.N (2$ 2 - >] 0жB >SODIUM(2 ?] 0J` t :11(2dB @] <D)P0Q A] 0Pp@ 0 0dB B]@ <D)PXP C] 0X0@ 0 0B \ s *޽h ? ̙33y___PPT10Y+D=' = @B +  0L0 /'goaŗ(  `^B ` 6Do3^B ` 6Do%3W ^B ` 6Do NDn ^B ` 6Do h: ^B  ` 6DoQ d ^B  ` 6Do K ^B  ` 6Do E^B  ` 6Do8 ?R2  ` s *f>iR2 ` s *fcLR2 ` s *f5 l R2 ` s *f s oR2 ` s *fb R2 ` s *f lu R2 ` s *fI  R2 ` s *f :- L  Df `# Q > 7` ` 01f` ` 01Df` ` 01f` ` 01$f` ` 01!f8T Zo `# 0 EWfB ` 6DjJoofB `B 6DjJZo8T Zo `# \ qWfB ` 6DjJoofB  `B 6DjJZo8T Zo !`#  WfB "` 6DjJoofB #`B 6DjJZo8T Zo $`#  WfB %` 6DjJoofB &`B 6DjJZo8T Zo '`# 2 GWfB (` 6DjJoofB )`B 6DjJZo8T Zo *`# ^ sWfB +` 6DjJoofB ,`B 6DjJZo8T Zo -`#  WfB .` 6DjJoofB /`B 6DjJZo8T Zo 0`#  WfB 1` 6DjJoofB 2`B 6DjJZo8T Zo 3`#  YfB 4` 6DjJoofB 5`B 6DjJZo8T Zo 6`#  1YfB 7` 6DjJoofB 8`B 6DjJZo 9` 0Қ 2 D1s 2s 2p 2 X :` 01  kX ;` 01 N kX <` 01 kX =` 01. kX >` 01+ k0L Zo ?`# : O \fB @` 6DjJoofB A`B 6DjJZo0L Zo B`# f { \fB C` 6DjJoofB D`B 6DjJZo0L Zo E`#  \fB F` 6DjJoofB G`B 6DjJZo0L Zo H`#  \fB I` 6DjJoofB J`B 6DjJZo0L Zo K`# < Q \fB L` 6DjJoofB M`B 6DjJZo0L Zo N`# h } \fB O` 6DjJoofB P`B 6DjJZo0L Zo Q`#  \fB R` 6DjJoofB S`B 6DjJZo0L Zo T`#  \fB U` 6DjJoofB V`B 6DjJZo0L Zo W`#   ^fB X` 6DjJoofB Y`B 6DjJZo Z` 0<  D1s 2s 2p 2 X [` 01S X \` 01S . X ]` 01Sn X ^` 01S n X _` 01S k 0L Zo ``# a / fB a` 6DjJoofB b`B 6DjJZo0L Zo c`# aF [ fB d` 6DjJoofB e`B 6DjJZo0L Zo f`# a fB g` 6DjJoofB h`B 6DjJZo0L Zo i`# a fB j` 6DjJoofB k`B 6DjJZo0L Zo l`# a 1 fB m` 6DjJoofB n`B 6DjJZo0L Zo o`# aH ] fB p` 6DjJoofB q`B 6DjJZo0L Zo r`# a| fB s` 6DjJoofB t`B 6DjJZo0L Zo u`# c fB v` 6DjJoofB w`B 6DjJZo x` 0  q D1s 2s 2p 2 X y` 01{X z` 01{8 X {` 01{xX |` 01{xX }` 01{u0L Zo ~`# $9fB ` 6DjJoofB `B 6DjJZo0L Zo `# PefB ` 6DjJoofB `B 6DjJZo0L Zo `# fB ` 6DjJoofB `B 6DjJZo0L Zo `# fB ` 6DjJoofB `B 6DjJZo0L Zo `# &;fB ` 6DjJoofB `B 6DjJZo0L Zo `# fB ` 6DjJoofB `B 6DjJZo0L Zo `# fB ` 6DjJoofB `B 6DjJZo ` 0H&  D1s 2s 2p 2 X ` 01e X ` 01Ne X ` 01e X ` 01.e X ` 01+e 0L Zo `#  :OV fB ` 6DjJoofB `B 6DjJZo0L Zo `#  f{V fB ` 6DjJoofB `B 6DjJZo0L Zo `#  V fB ` 6DjJoofB `B 6DjJZo0L Zo `#  V fB ` 6DjJoofB `B 6DjJZo0L Zo `#  <QV fB ` 6DjJoofB `B 6DjJZo0L Zo `#  V fB ` 6DjJoofB `B 6DjJZo ` 0p<  D1s 2s 2p 2 X ` 01 J X ` 01 X ` 01 & X ` 01 & X ` 01 # 0L Zo `# % r fB ` 6DjJoofB `B 6DjJZo0L Zo `# % r fB ` 6DjJoofB `B 6DjJZo0L Zo `# % Vkr fB ` 6DjJoofB `B 6DjJZo0L Zo `# % r fB ` 6DjJoofB `B 6DjJZo0L Zo `# % r fB ` 6DjJoofB `B 6DjJZo ` 0  5  D1s 2s 2p 2 L V l  `#  J ` ` 01  l l ` ` 01  l 8T Zo `#   ] fB ` 6DjJoofB `B 6DjJZo8T Zo `#   ] fB ` 6DjJoofB `B 6DjJZo8T Zo `#   - ] fB ` 6DjJoofB `B 6DjJZo8T Zo `# D  Y ] fB ` 6DjJoofB `B 6DjJZo ` 0V  <1s 2s 2 X ` 017 ` X ` 017 9 0L Zo `# E  fB ` 6DjJoofB `B 6DjJZo0L Zo `# E ) fB ` 6DjJoofB `B 6DjJZo0L Zo `# E l fB ` 6DjJoofB `B 6DjJZo ` 0! U  <1s 2s 2 L Hr . `# ` ` 01) .8T Zo `# fB ` 6DjJoofB `B 6DjJZo8T Zo `#   fB ` 6DjJoofB `B 6DjJZo ` 0'Hr  81s 2 X ` 01mi0L Zo `#  |ZfB ` 6DjJoofB `B 6DjJZo ` 0,8 81s 2 |L D  `#  fB ` 6DjJ  D fB ` 6DjJ  fB ` 6DjJ fB ` 6DjJ  fB ` 6DjJ- - fB ` 6DjJ fB ` 6DjJ fB ` 6DjJfB ` 6DjJ fB ` 6DjJa afB ` 6DjJi ifB ` 6DjJ L  < Pb  `#  J3fB ` 6DjJ > P> fB ` 6DjJ$B $b fB ` 6DjJ>B >b fB ` 6DjJ` B ` b fB ` 6DjJ@ B @ b fB ` 6DjJz ? z _ fB ` 6DjJ B b fB a 6DjJ B b fB a 6DjJ? b fB a 6DjJ< _ fB a 6DjJ? b fB a 6DjJ? b fB a 6DjJ? b ^B a 6DoH O a 07 P] C ATOMIC NUMBER 2  a 6<8m  t 1st IONISATION ENERGY / kJmol-18! 2    R2  a s *f ^B  a 6Do= X a 01 8  X a 01 t  X a 01  t  X a 01   X a 01   X a 01 X  0L Zo a#   fB a 6DjJoofB aB 6DjJZo0L Zo a#    fB a 6DjJoofB aB 6DjJZo0L Zo a#  D Y  fB a 6DjJoofB aB 6DjJZo0L Zo a#  p  fB a 6DjJoofB aB 6DjJZo0L Zo  a#   fB !a 6DjJoofB "aB 6DjJZo0L Zo #a#    fB $a 6DjJoofB %aB 6DjJZo0L Zo &a#  " 7  fB 'a 6DjJoofB (aB 6DjJZo0L Zo )a#  N c  fB *a 6DjJoofB +aB 6DjJZo0L Zo ,a#   fB -a 6DjJoofB .aB 6DjJZo0L Zo /a#   fB 0a 6DjJoofB 1aB 6DjJZo0L Zo 2a#     fB 3a 6DjJoofB 4aB 6DjJZo 5a 0N9  Q1s 2s 2p 3s  2 R2 6a s *f vL  7a#  ~ ` 8a 01XX` 9a 01X` :a 014X` ;a 01X4` a# ffB ?a 6DjJoofB @aB 6DjJZo8T Zo Aa#  f!fB Ba 6DjJoofB CaB 6DjJZo8T Zo Da# dfyfB Ea 6DjJoofB FaB 6DjJZo8T Zo Ga# ffB Ha 6DjJoofB IaB 6DjJZo8T Zo Ja# ffB Ka 6DjJoofB LaB 6DjJZo8T Zo Ma# f#fB Na 6DjJoofB OaB 6DjJZo8T Zo Pa# BfWfB Qa 6DjJoofB RaB 6DjJZo8T Zo Sa# nffB Ta 6DjJoofB UaB 6DjJZo8T Zo Va# hfB Wa 6DjJoofB XaB 6DjJZo8T Zo Ya# hfB Za 6DjJoofB [aB 6DjJZo8T Zo \a# (f=fB ]a 6DjJoofB ^aB 6DjJZo8T Zo _a# TfifB `a 6DjJoofB aaB 6DjJZo ba 0_v Q1s 2s 2p 3s  2 ^B ca 6Do  R2 da s *E  R2  a s *f =  ea 0epw "Variation in 1st Ionisation Energy #(2#  ga <i̙1?@0 7EXPLANATION The value for Magnesium is higher than for Sodium due to the increased nuclear charge. There is no extra shielding. The trend is similar to that at the start of the 2nd period. ^ (2 2   ha 0dsB A MAGNESIUM (2  ia 0wJ :12(2dB ja <D)P0Q ka 0Pp@ 0 0dB la@ <D)PXP ma 0X0@ 0 0B ` s *޽h ? ̙33y___PPT10Y+D=' = @B +  0L0    3 ( w    0w |Successive Ionisation Energies (2  X  0P0  Atoms with more than one electron can have them successively removed. 2nd I.E. The energy required to remove one mole of electrons (to infinity) from one mole of gaseous unipositive ions to form one mole of gaseous dipositive ions. e.g. Na+(g) Na2+(g) + e- Al+(g) Al2+(g) + e- Trends Successive ionisation energies are always greater than the previous one Reason :- the electron is being pulled away from a more positive species Large increases occur when there is a change of shell Reason :- there is a big decrease in shielding Large increases can be used to predict the group of an unknown element F$RL82J fFff4 Y ffffffffffffffffIKff5f1JfZ   "      dB  <DjJ( (dB  <DjJ0 0  6ܵ? cSee next slide for an example*(2  B亞))?i`x tMake sure you write in the (g):(2dB  <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0B  s *޽h ? ̙33y___PPT10Y+D=' = @B +g 0L0 vn #| ( w |x  | <A R??P  R | 00   I.E. kJmol-1 Electronic configuration 1 590 1s2 2s2 2p6 3s2 3p6 4s2 2 1145 1s2 2s2 2p6 3s2 3p6 4s1 3 4912 1s2 2s2 2p6 3s2 3p6 4 6474 1s2 2s2 2p6 3s2 3p5 5 8145 1s2 2s2 2p6 3s2 3p4 6 10496 1s2 2s2 2p6 3s2 3p3 7 12320 1s2 2s2 2p6 3s2 3p2 8 14207 1s2 2s2 2p6 3s2 3p1 9 18192 1s2 2s2 2p6 3s2 10 20385 1s2 2s2 2p6 3s1 11 57048 1s2 2s2 2p6 12 63333 1s2 2s2 2p5 13 70052 1s2 2s2 2p4 14 78792 1s2 2s2 2p3 15 86367 1s2 2s2 2p2 16 94000 1s2 2s2 2p1 17 104900 1s2 2s2 18 111600 1s2 2s1 19 494790 1s2 20 527759 1s1` @ fff                                      f f f f f f f f f f                                                                                                                                                                             ^B | 6D p  | 6K̙?  7A(2 | 0ٞw )Successive Ionisation Energies of Calcium *(2* | | 0N p The 3rd I.E. is significantly higher than the 2nd I.E. because the third electron is coming out of a 3p orbital, nearer the nucleus and subjected to less shielding. More energy is needed to overcome the attraction of the nucleus.  2 | 6R̙? 8 7A(2dB | <D)P0Q | 0Pp@ 0 0dB  |@ <D)PXP !| 0X0@ 0 0B | s *޽h ? ̙33y___PPT10Y+D=' = @B +F 0L0 UM (  x  <A {??P  {^B  6D    6[̙?@ 7B(2  0\^w )Successive Ionisation Energies of Calcium *(2* {  0xc"` o The 11th I.E. is significantly higher than the 10th I.E. because the eleventh electron is coming out of the second main energy level, not the third. It is much nearer the nucleus and is subjected to less shielding. 2  6i̙? P 7B(2dB  <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0  0@0k   I.E. kJmol-1 Electronic configuration 1 590 1s2 2s2 2p6 3s2 3p6 4s2 2 1145 1s2 2s2 2p6 3s2 3p6 4s1 3 4912 1s2 2s2 2p6 3s2 3p6 4 6474 1s2 2s2 2p6 3s2 3p5 5 8145 1s2 2s2 2p6 3s2 3p4 6 10496 1s2 2s2 2p6 3s2 3p3 7 12320 1s2 2s2 2p6 3s2 3p2 8 14207 1s2 2s2 2p6 3s2 3p1 9 18192 1s2 2s2 2p6 3s2 10 20385 1s2 2s2 2p6 3s1 11 57048 1s2 2s2 2p6 12 63333 1s2 2s2 2p5 13 70052 1s2 2s2 2p4 14 78792 1s2 2s2 2p3 15 86367 1s2 2s2 2p2 16 94000 1s2 2s2 2p1 17 104900 1s2 2s2 18 111600 1s2 2s1 19 494790 1s2 20 527759 1s1@ @ fff                                                                                                                                                                                                                              B  s *޽h ? ̙33y___PPT10Y+D=' = @B +1 0L0 @8 ( w x  <A }??P  }^B  6D@0p   6\̙?PV 7C(2  0vw )Successive Ionisation Energies of Calcium *(2*   0"` o0 The 19th I.E. is significantly higher than the 18th I.E. because the electron being removed is from the first main energy level. It is much nearer the nucleus and is subjected to no shielding - its value is extremely large. 2  6 ̙? P 7C(2dB  <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0  00  k  I.E. kJmol-1 Electronic configuration 1 590 1s2 2s2 2p6 3s2 3p6 4s2 2 1145 1s2 2s2 2p6 3s2 3p6 4s1 3 4912 1s2 2s2 2p6 3s2 3p6 4 6474 1s2 2s2 2p6 3s2 3p5 5 8145 1s2 2s2 2p6 3s2 3p4 6 10496 1s2 2s2 2p6 3s2 3p3 7 12320 1s2 2s2 2p6 3s2 3p2 8 14207 1s2 2s2 2p6 3s2 3p1 9 18192 1s2 2s2 2p6 3s2 10 20385 1s2 2s2 2p6 3s1 11 57048 1s2 2s2 2p6 12 63333 1s2 2s2 2p5 13 70052 1s2 2s2 2p4 14 78792 1s2 2s2 2p3 15 86367 1s2 2s2 2p2 16 94000 1s2 2s2 2p1 17 104900 1s2 2s2 18 111600 1s2 2s1 19 494790 1s2 20 527759 1s1" @ fff                                                                                                                                                                                                                               B  s *޽h ? ̙33y___PPT10Y+D=' = @B +9 0L0 H@(  x  <A L??P  L^B  6D ^B  6D@0p^B   6D p    6, ̙?PV 7C(2   6H$̙?@ 7B(2   6@(̙?  7A(2   04,w )Successive Ionisation Energies of Calcium *(2*   0h0 (z +SUMMARY Wherever there has been a large increase in Ionisation Energy there has been a change in energy level from which the electron has been removed.Rxg,4 ^dB  <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0[  0P0   I.E. kJmol-1 Electronic configuration 1 590 1s2 2s2 2p6 3s2 3p6 4s2 2 1145 1s2 2s2 2p6 3s2 3p6 4s1 3 4912 1s2 2s2 2p6 3s2 3p6 4 6474 1s2 2s2 2p6 3s2 3p5 5 8145 1s2 2s2 2p6 3s2 3p4 6 10496 1s2 2s2 2p6 3s2 3p3 7 12320 1s2 2s2 2p6 3s2 3p2 8 14207 1s2 2s2 2p6 3s2 3p1 9 18192 1s2 2s2 2p6 3s2 10 20385 1s2 2s2 2p6 3s1 11 57048 1s2 2s2 2p6 12 63333 1s2 2s2 2p5 13 70052 1s2 2s2 2p4 14 78792 1s2 2s2 2p3 15 86367 1s2 2s2 2p2 16 94000 1s2 2s2 2p1 17 104900 1s2 2s2 18 111600 1s2 2s1 19 494790 1s2 20 527759 1s1 @ fff                                                                                                                                                                                                                           B  s *޽h ? ̙33y___PPT10Y+D=' = @B + 0L0  4(    0w I QUESTION TIME (2   0L0  SWhich has the higher value, the 3rd I.E. of aluminium or the 3rd I.E. of magnesium?T 2T,   0ȉHX EQ.1&(2   6\̙? 4 UCLICK HERE FOR THE ANSWER (2  0 4@ 0 0dB  <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0B  s *޽h ? ̙33y___PPT10Y+D=' = @B +p 0L0 w  ( @   0|w I QUESTION TIME (2  0|L0  PWhich has the higher value, the 1st I.E. of sodium or the 2nd I.E. of magnesium?Q 2Q  0Hp EQ.2&(2   6̙? 4 UCLICK HERE FOR THE ANSWER (2   6 4@ 0 0dB  <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0B  s *޽h ? ̙33y___PPT10Y+D=' = @B + 0L0  0(    0Lw I QUESTION TIME (2  0tXH gAns.(2   0и Z The 3rd I.E. of magnesium EXPLANATION The 3rd I.E. of aluminium involves the following change... Al2+(g) Al3+(g) 1s2 2s2 2p6 3s1 1s2 2s2 2p6 The 3rd I.E. of magnesium involves the following change& Mg2+(g) Mg3+(g) 1s2 2s2 2p6 1s2 2s2 2p5 Despite magnesium having 12 protons in its nucleus and aluminium having 13, more energy is required to remove the third electron from magnesium. This is because the electron being removed is coming from an orbital closer to the nucleus. There is less shielding and therefore a greater effective nuclear charge. The electron is thus held more strongly. 202R 29 202`V9  +hE 9   O 8  dB   <DjJ @x dB   <DjJ0h dB   <D)P0Q   0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0  T Ԕ))? u CQ.2$(2  0̙  u@4 0 0   0DL0  SWhich has the higher value, the 3rd I.E. of aluminium or the 3rd I.E. of magnesium?T 2T,   0HX EQ.1&(2B  s *޽h ? ̙33y___PPT10Y+D=' = @B + 0L0 @ }(    0 w I QUESTION TIME (2   0XthH iAns0(2(   0L0  The 2nd I.E. of magnesium EXPLANATION The 1st I.E. of sodium involves the following change Na(g) Na+(g) 1s2 2s2 2p6 3s1 1s2 2s2 2p6 The 2nd I.E. of magnesium involves the same change in electron configuration& Mg+(g) Mg2+(g) 1s2 2s2 2p6 3s1 1s2 2s2 2p6 However, magnesium has 12 protons in its nucleus, whereas sodium only has 11. The greater nuclear charge means that the electron being removed is held more strongly and more energy must be put in to remove it.f 202I 2N 202J S |d   c   dB   <DjJ  dB   <DjJ dB  <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0  0FL0  PWhich has the higher value, the 1st I.E. of sodium or the 2nd I.E. of magnesium?Q 2Q  04LHp EQ.2&(2B  s *޽h ? ̙33y___PPT10Y+D=' = @B +d   0L0 s k P  (    0Rw JREVISION CHECK (2  0V ZWhat should you be able to do? (2   0D\s  aRecall the definition of 1st Ionisation Energy Understand why energy is needed to remove an electron from an atom / ion Write equations representing 1st Ionisation Energy Know the trend in 1st Ionisation Energy across periods Explain, in terms of electron configuration, the trend across a given period Know the trend in 1st Ionisation Energy down groups Explain the trend down a given group Know, and explain, why successive Ionisation Energies get bigger Explain why there is sometimes a large jump between successive values Predict which group an element is in from its Ionisation Energies b 2f-f f?ff0ff4ffGff1ff"ffff1ff@ff;ffft u  | `      00w 8 ~,CAN YOU DO ALL OF THESE? YES NO6- 2!    0 H@@P 0 0   0f h8@U 0 0dB   <D)P0Q  0Pp@ 0 0dB @ <D)PXP  0X0@ 0 0H  0޽h ? ̙33y___PPT10Y+D=' = @B +  0L0 p ;(  9  0  YYou need to go over the relevant topic(s) again Click on the button to return to the menudG(282/$f f) f  s * x  P @S 0 0dB  <D)P0Q  0Pp@ 0 0dB @ <D)PXP   0X0@ 0 0H  0޽h ? ̙33y___PPT10Y+D=' = @B +  0L0  D(    0xK (WELL DONE! 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